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nydimaria [60]
3 years ago
7

Help can some one do number 10 please

Mathematics
1 answer:
marissa [1.9K]3 years ago
6 0
Download Socratic it'll do everything
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For each of the equations below, solve for y in terms of x. !<br> a. 2x – 3y = 12
ira [324]

Answer:

\large\boxed{y=\dfrac{2}{3}x-4}

Step-by-step explanation:

2x-3y=12\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\2x-2x-3y=12-2x\\\\-3y=12-2x\qquad\text{divide both sides by (-3)}\\\\\dfrac{-3y}{-3}=\dfrac{12}{-3}+\dfrac{-2x}{-3}\\\\y=-4+\dfrac{2}{3}x

7 0
3 years ago
If the starting population of 5 rabbits grows at 200% each year, how many will there be 20 years?
alina1380 [7]
Growth rate = 200% each year
SO population becomes twice in each year

After 20 years, population = 5* 2^20 = 5242880


(Assuming no deaths occur)

5 0
3 years ago
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What is the domain of f(x) = 2|x - 3| + 1 ?
defon

Domain: all reals, (-∝, ∝)

All inputs for x result in a solution.

7 0
2 years ago
Which is the graph of the following equation?
lesantik [10]

Given equation is

\frac{(x-5)^2}{16} - \frac{(y-2)^2}{9}=1

The given equation is in the form of

\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2}=1

a^2= 16  , so a=4

b^2 = 9 so b= 4

The value of 'a' is greater than the value of 'b'

So it is a Horizontal hyperbola

First two graphs are horizontal hyperbola

Here center is (h,k)  

h= 5 and k =2 from the given equation

So center is (5,2)

Now we find vertices

Vertices are (h+a,k)  and (h-a,k)

We know h=5, k=2  and a=4

So vertices are (9,2)  and (1,2)

Second graph having same vertices and center

The correct graph is attached below


7 0
3 years ago
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What is the area of the triangle? btw this ⌜ is on the right side<br><br> urgent<br> ◢2<br> 2
RoseWind [281]
It equals 4 my man ye
4 0
3 years ago
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