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3 years ago

Please help me Tramserran mam...

Mathematics

1 answer:

n200080 [17]3 years ago

4 0

Answer: see proof below

Step-by-step explanation:

Use the following when solving the proof...

Double Angle Identity: cos2A = 1 - 2sin²B

Pythagorean Identity: cos²A + sin²A = 1

note that A can be replaced with B

Proof from LHS → RHS

Given: cos²A + sin²A · cos2B

Double Angle Identity: cos²A + sin²A(1 - 2sin²B)

Distribute: cos²A + sin²A - 2sin²A·sin²B

Pythagorean Identity: 1 - 2sin²A·sin²B

Pythagorean Identity: cos²B + sin²B - 2sin²A·sin²B

Factor: cos²A + sin²B(1 - 2sin²A)

Double Angle Identity: cos²B + sin²B · cos2A

cos²B + sin²B · cos2A = cos²B + sin²B · cos2A $\checkmark$

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3 years ago

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3 years ago

Please help me Tramserran mam...​

Please help me Tramserran mam...