15:24 is divisible by 3, simplifying it down to 3:8. 19:24, 7:8, and 6:8 are all obviously larger than this ratio, and 1:2 can be equalized to 4:8, which is also bigger than 3:8, so none of the answer choices are less than 15:24.
Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 9 rolls, hence
.
- Of the six sides, 2 are 3 or 4, hence

The desired probability is:

In which:

Then



Then:


0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For more on the binomial distribution, you can check brainly.com/question/24863377
Answer:
35/16 sec ( 2 3/16 sec)
Step-by-step explanation:
This assumes you glove is at height = 0
0 = -16t^2 + 35t
0 = t ( -16t + 35) shows t = 0 ( before you throw it) and t = 35/16 sec
Answer:

and

Step-by-step explanation:
First make all the fractions into improper fractions

After doing that put them back into the problems
Problem 1)
÷
, plug in the improper fractions
÷
to divide, you need to flip the second fraction and multiply
·
=
then reduce

Problem 2)
÷
Plug in improper fraction
÷
Then flip second fraction and multiply
·
Multiply
Reduce, or make it a mixed number
