<h3>Answer: B) 31.348</h3>
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Work Shown:
We will never use the alpha = 0.05 value when computing the test statistic. So we can ignore alpha for this particular problem.
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n = 40 is the sample size.
s = 2.6 is the sample standard deviation
= sigma = 2.9 is the population standard deviation (ie the claimed standard deviation for all the pay phones)
Test Statistic for chi-square
The total distance between the two women would simply be
the sum of the hypotenuse formed by the triangular path they created.
For each women:
<span>c^2 = a^2 + b^2</span>
c^2 = 3^2 + 4^2
c^2 = 9 + 16
c^2 = 25
c = 5 m
Therefore the distance between the two is:
distance between the two women = 2 * c
<span>distance between the two women = 10 m</span>
<h3>Sample space = {a,b,c,d,e,f}</h3><h3>Event space = {a,c}</h3>
We simply list all of the letters mentioned as they are the possible outcomes. We can only pick one item from the sample space. The event space is the set of outcomes where we want to happen (picking either an 'a' or 'c').
The area of a trapezoid with base lengths 7 in and 19 in is given by
A = (1/2)(b1 + b2)h
A = (1/2)(7 +19)·7 = 91
The appropriate choice is
D. 91 in²
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It can also be figured by adding the area of the 7 in square (49 in²) to the area of the 7×12 in right triangle (42 in²).
