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Genrish500 [490]
2 years ago
11

51 is 33 1/3 of what number?

Mathematics
1 answer:
Makovka662 [10]2 years ago
5 0

1700, just use the inverse operation. The problem would look like this ( not inverse operation ) x ÷ 33 1/3 = 51

All you have to do is multiply the two numbers.

51 x 33 1/3 = 1700

Now plug it back in and check

1700 ÷ 33 1/3 does indeed equal 51.


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How many solutions are there to the equation below 9x + 27 = 9( x + 2 ) + 9
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Let's solve the equation:

9x+27 = 9(x+2)+9 ← Distribute 9 to the x and 2

9x+27 = 9x+18+9 ← Combine like terms

9x+27 = 9x + 27 ← Subtract 27 from both sides

9x = 9x


Infinitely many solutions would be correct because no matter what x is, it will always equal each other the both sides of the equation because it is 9 times x on both sides.


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Sociology graduates, upon entering the workforce are normally distributed and earn a mean salary of $30,000 with a standard devi
GrogVix [38]

Answer:

0.62% probability that randomly chosen salary exceeds $40,000

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 30000, \sigma = 4000

What is the probability that randomly chosen salary exceeds $40,000

This is 1 subtracted by the pvalue of Z when X = 40000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40000 - 30000}{4000}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938 = 0.0062

0.62% probability that randomly chosen salary exceeds $40,000

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161051 is the answer!!!!!!!
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