Answer:
3.5132719e+24
Step-by-step explanation:
<em>x = markers</em>
<em>y = colored pencils</em>
12x = y
x= 72
y = 6
Okay, so what I did was divide 78 by 12 (to find the number of colored pencils) which gave me 6.5. You can't have half a colored pencil, so I rounded the number down to get 6. To find the number of markers, I multiplied 12 and 6 <em>(12x = 6) </em>which gave me 72. To check my answer I added the two amounts, 72 + 6, which gave me 78.
The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers
two consecutive even integers: n, n+2
next two consecutive even integers n+4, n+6
n+(n+2) >= 7+1/2(n+4 +n+6)
combine like terms
2n+2 >= 7 +1/2(2n+10)
distribute 1/2
2n+2 >= 7+n+5
2n+2>= n+12
subtract n from each side
n+2>= 12
subtract 2 from each side
n>10
4 integers : 10, 12 ,14, 16
Remember
(x^m)^n=x^(mn)
and
(x^m)(x^n)=x^(m+n)
and
(x^m)/(x^n)=x^(m-n)
so
(4^2)^3=4^(2*3)=4^6
notice
4^6=(2^2)^6=2^2*6)=2^12
(4/2)^3=2^3
on top we have
(2^12)(2^3)(2^3)=2^(12+3+3)=2^18
on bottom
8^3
conver to base 2
(2^3)^3=2^(3*3)=2^9
now we have
(2^18)/(2^9)=2^(18-9)=2^9
Step-by-step explanation:
x+5=36
or, x=36-5
or, x=31
The value of x=31
