Use the steps to solve the Carbon Dating Problem.

Mathematics

1 answer:

scZoUnD [109]3 years ago

5 0

On my graph, the whole number closest to that point is 32,194.

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If the point is (-4,2) what the reflection over y=x

DiKsa [7]

Answer:

(2,-4)

Step-by-step explanation:

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places.

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3 years ago

What is the first step in solving quadratic equations by finding square roots? a. give the positive and negative answer c. squar

daser333 [38]

Answer:

C: isolate the x squared by using inverse operations

Step-by-step explanation:

This method of solving quadratic equation is used when there is only x² term and no x term. Thus;

For example, we have a quadratic equation;

x² - 1 = 80

To solve this by square root method, the first step we have to take is to isolate the x² term by inverse operation which is by addition of 1 to both sides to get rid of the -1 on the left side so that x² can be isolated.

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3 years ago

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$