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Alex73 [517]
3 years ago
15

What is between 68 2/3 and 72 1/2 (options) 68 3/10, 747/11, 68 1/2, 550/8

Mathematics
2 answers:
spin [16.1K]3 years ago
4 0
You can do this by converting all fractions to decimal form

68 2/3  = 68.66666...   72 1/2  = 72.5

68 3/10 = 68.3, 747/11 =  67.909, 68 1/2 = 68.5 and 550/8 =  68.75

so we see that 68.75  ( that is 550/8) is the correct option
enyata [817]3 years ago
3 0
Why not write all of the numbers in decimal fraction form, to make them easier to compare?

68 2/3 = 68.666...
72 1/2 = 72.500
68 3/10 = 68.300
74 7/11 = 74.636...
68 1/2  = 68.500
550/8 = 68.750

Now ask yourself:  Which of the last four numbers is between 68.666.. and 72.500?
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How would you write the following expression as a sum or difference? `"log"(root(3)(2 - x)/(3x))`
pashok25 [27]

<h3>log [ (√3)(2 - x)/(3x) ] = log (2 - x) - ¹/₂ log 3 - log x</h3>

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }

\boxed { (a ^ b) ^ c = a ^ { b . c } }

\boxed {a ^ b \div a ^ c = a ^ { b - c } }

\boxed {\log a + \log b = \log (a \times b) }

\boxed {\log a - \log b = \log (a \div b) }

<em>Let us tackle the problem!</em>

\texttt{ }

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log \sqrt{3} + \log (2-x) - \log (3x)

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log 3^{1/2} + \log (2-x) - (\log 3 + \log x)

\log \frac{\sqrt{3}(2-x)}{(3x)} = \frac{1}{2} \log 3 + \log (2-x) - \log 3 - \log x

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log (2-x) - \frac{1}{2}\log 3 - \log x

\texttt{ }

<h3>Learn more</h3>
  • Coefficient of A Square Root : brainly.com/question/11337634
  • The Order of Operations : brainly.com/question/10821615
  • Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

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so when you multiply, you multiply both on the top and on the bottom, so this would be:
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Step-by-step explanation:

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