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2 years ago

What is 275% in simplest form

2 answers:

4 0

It would be 11/40 you would just put it over 1000 in this case and the divide by 5 and then reduce the fraction if possible like this would be 55/200 so you would divide again to get 11/40

olya-2409 [2.1K]2 years ago

3 0

2.75 i think,, 275 divided by 100=2.75

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(I’m marking brainliest) plzzz help me out!!!

larisa86 [58]

Answer:

14, 16, 18, 20

Step-by-step explanation:

4 0

2 years ago

What is another solution of the equation x + y = 7?

White raven [17]

X=3, y=4
x=-2, y=9
Set x equal to anything, then isolate y to get the other number.

5 0

3 years ago

15y+31=61 how do I solve this

Setler79 [48]

15y + 31 = 61
15y = 61 - 31
15y = 30
y = 30 ÷ 15
y = 2

6 0

3 years ago

He rain caused the river to ride a total of 6 2/3 inches. The river was rising at an average of 2/3 of an inch each hour. How ma

Kobotan [32]

To find out how many hours it rained, divide the total rise in the river by the amount it rose every hour.

$\sf 6\dfrac{2}{3}\div\dfrac{2}{3}$

First convert the mixed number into an improper fraction. We do this by multiplying the denominator to the whole number, adding it to the numerator, which becomes our new numerator, and we keep the denominator the same:

$\sf\dfrac{20}{3}\div\dfrac{2}{3}$

When dividing fractions we flip(the reciprocal) the one we're dividing by and multiply:

$\sf\dfrac{20}{3}\times\dfrac{3}{2}$

Multiply the numerators and denominators together:

$\sf\dfrac{60}{6}$

Simplify by dividing:

$\boxed{\sf 10}$

So it rained for 10 hours.

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20lnx%20%7D%20" id="TexFormula1" title=" \sqrt[4]{ lnx } " alt=" \sqrt[4]

Kamila [148]

Use the power rule for differentiation:

$\dfrac{\text{d}}{\text{d}x} (f(x))^k = k(f(x))^{k-1}f'(x)$

You can use this formula if you remember that a root is just a rational exponential:

$\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}$

So, remembering that the derivative of the logarithm is 1/x, you have

$\dfrac{\text{d}}{\text{d}x} (\ln(x))^{\frac{1}{4}} = \frac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x}$

Which you can rewrite as

$\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}$

3 0

2 years ago