The graph shows a system consisting of a linear equation and a quadratic equation. What is the solution to the system?

A diver descends at a steady rate of 2.54 meters every hour. Yesterday, he dove to a depth of 18 meters. Which expression can yo

dimulka [17.4K]

18 divided by 2.54

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The side lengths of the base of this right triangular prism are 3 ft, 4 ft, and 5 ft. The height of the prism is 9 ft. What is t

Sladkaya [172]

Answer:

480

Step-by-step explanation:

5 0

2 years ago

Need help on question 5 please help

blagie [28]

Answer:

$66

Step-by-step explanation:

It can be convenient to assign a different variable to the amount of money each spent. We can call the amounts spent by Seedevi, Georgia, and Amy "s", "g", and "a", respectively.

The problem statement tells us ...

s = (1/2)g

s = a +6

s + g + a = 258

__

The problem statement asks for the amount Seedevi spent, so we need to find the value of s. It is convenient to write the other variables in terms of s:

g = 2s

a = s -6

Then the sum is ...

s + (2s) +(s -6) = 258

4s = 264 . . . . . . . . . . . add 6, simplify

s = 66 . . . . . . . . . . . . . .divide by 4

Seedevi spent $66.

4 0

3 years ago

Please help!!!

trasher [3.6K]

When an answer to a question uses the greater than symbol, that means any number above the number used is a possible answer to the equation. However, when it's just a simple "x = 2", then 2 is the only possible answer to that equation. Think about it as if it were on a graph. In the attached file I have a graph that is displaying the equation "x > 4". The entire shaded area to the right of 4 could be a possible answer.

Hope this helps.

6 0

2 years ago

A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :

const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that $n = 1067, \pi = \frac{74}{1067} = 0.069$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079$

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0

2 years ago