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Travka [436]
3 years ago
11

Is 64x15=32x30 true or false

Mathematics
1 answer:
Law Incorporation [45]3 years ago
3 0

the equation is true,

the answer is 960

64x15 = 960

32×30= 960

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Solve for x and y. Geometry
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Answer:

x =106.5

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Step-by-step explanation:

Angle x is 1/2 arc SPQ

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3 years ago
3/7h=33 ill give brainlyest if i can
loris [4]
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step by step explanation
8 0
3 years ago
In each part, decide if the statement is true. If it is true, prove it. If it is not true, give an explicit counterexample and d
svet-max [94.6K]

Answer: Hello!

ok, remember that "if and only if" implies that you need to prove the statement in both ways, this is represented with the ⇔ usually.

a) For any sets A, B and C, A ∩ B ⊆ C if and only if either A ⊆ C or B ⊆ C.

In this type of problems, i  find very useful start looking for some counterexample.

In this case, suppose that A = {1,2,3,4,5} , B = {3,4,5,6,7} and C = {3,4,5,6}

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And A∩B = {3,4,5}

then A∩B ⊂ C

then the statement is false (because one of the ways is false, remember that this is an "if and only if" statement)

b) For any sets A, B and C, A ⊆ B ∩ C if and only if both A ⊆ B and A ⊆ C.

the first way is true; because if A ⊆ B ∩ C. then all the elements of A are in the intersection of B and C (which are common elements for B and C) and then all the elements of A are in the set B and in the set C, and this means that A ⊆ B and A ⊆ C.

But let's see the other way now, suppose that A ⊆ B and A ⊆ C, now we want to know if A ⊆ B ∩ C.

if A ⊆ B and A ⊆ C, means that all the elements of A are in B, and all the elements of A are in C, then all the elements of A are common elements between B and C, this means that B ∩ C is at least equal to A (at least, because we know that all the elements of A are common elements between B and C, but there could be more common elements that don belong to A)

then A ⊆ B ∩ C.

4 0
3 years ago
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