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asambeis [7]
3 years ago
12

Need help!!!!!!!!!!!!!!

Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer:

1. Right

2. Equiangular

3. Obtuse

4. Equiangular

5. Obtuse. This is because obtuse triangles have angles greater than 90°

6. Equiangular. This is because an equiangular triangle is easier to build than the other types of triangles

<em>PLEASE DO</em><em> </em><em>MARK ME</em><em> </em><em>AS BRAINLIEST</em><em> </em><em>IF</em><em> </em><em>MY </em><em>ANSWERS</em><em> </em><em>ARE</em><em> </em><em>HELPFUL</em><em> </em><em>;</em><em>)</em>

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Class intervals in a grouped frequency distribution are given as 4−11, 12−19, 20−27, 28−35, 36−43. Write the next two class inte
SpyIntel [72]

Answer:

<h3>{44-55}</h3><h3>{52- 59 } are the last two interval s</h3>

Step-by-step explanation:

<h2>To get the class boundaries deduct 0.5 from the first number and add 0.5 to the second number = 4-0.5 = 3.5 </h2><h2> = 11.5 + 0.5 = 11.5 </h2><h2> = 3.5 -11.5 as in the fish class boundary .</h2><h2>same for all other boundaries</h2>

8 0
3 years ago
PLEASE HELP GIVING BRAINLEST
Softa [21]

Answer:

Step-by-step explanation:

1. 34

2.12

3. 45

5 0
3 years ago
PLSS HELP!! VERY EASY.
gogolik [260]

Answer:

35 ways

Step-by-step explanation:

Alex has 9 friends and wants to invite 5 friends. Since Alex requires two of his friends who are twins to come together to his birthday party, since the two of them form a group, the number of ways we can select the two of them to form a group of two is ²C₂ = 1 way.

Since we have removed two out of the nine friends, we are left with 7 friends. Also, two friends are already selected, so we are left with space for 3 friends. So, the number of ways we can select a group of 3 friends out of 7 is ⁷C₃ = 7 × 6 × 5/3! = 35 ways.

So, the total number ways we can select 5 friend out of 9 to  party come to the birthday include two friends is  ²C₂ × ⁷C₃ = 1 × 35 = 35 ways

3 0
3 years ago
I really need help with this
BabaBlast [244]

Answer:

  • A  (-4, 1)
  • B  (2, 5)

Step-by-step explanation:

The current endpoints are ...

  V = (-9, 2)

  W = (-3, 6)

Put each of these in the translation formula to see where the image points are.

  (x, y) ⇒ (x+5, y-1)

  (-9, 2) ⇒ (-9+5), 2-1) = (-4, 1) . . . . point V ⇒ V'

  (-3, 6) ⇒ (-3+5, 6-1) = (2, 5) . . . . . point W ⇒ W'

The new end points are (-4, 1) and (2, 5), matching choices A and B.

7 0
3 years ago
Please help me with this!!!!!!!!!!!!!!!!!!!!!!!!!1
Reika [66]

Answer:

here you goooooooooooo!!!!  lol

4 0
3 years ago
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