Answer:
don't get what
Step-by-step explanation:
..................
Answer:
the correct answer is the product of PA) and P(B) is not equal to P(A and B)
The average rate of change over some interval [a, b] is equal to the slope of the secant line from (a, h(a)) to (b, h(b)).
h(t) is a quadratic function, so its graph is a parabola, and in particular it's one that has a minimum of -4 when t = 2.
The secant line over an interval [a, b] will have a negative slope if the distance from a to 2 is larger than the distance from b to 2.
(A) If a = 4 and b = 5, then |a - 2| = 2 and |b - 2| = 3, so the slope and hence average rate of change is positive.
(B) If a = -1 and b = 5, then |a - 2| = 3 and |b - 2| = 3, so this ARoC is zero.
(C) If a = 0 and b = 4, then |a - 2| = 2 and |b - 2| = 2, so this ARoC is also zero.
(D) If a = -1 and b = 4, then |a - 2| = 3 and |b - 2| = 2, so this ARoC is negative.
Answer:
Step-by-step explanation:
f(x)/g(x)=(6x+2)/(x-7)
The only restriction upon the domain, possible values of x, is division by zero is undefined. So x cannot equal 7.
So the domain is all real numbers except 7. In interval notation the domain is
x=(-oo, 7),(7, +oo)
We have that
<span>A(-6,-5) and B (4,0)
we know that
</span><span>AP:PB is 2:3
so
(2+3)=5
AP=2/5
PB=3/5
step 1
find the x coordinate of P
Px=Ax+AP*ABx
where
Ax is the x coordinate of A
AP is 2/5
ABx is the distance AB in the x coordinate
so
PX=[-6+(2/5)*(4+6)]------>Px=-2
</span>step 2
find the y coordinate of P
Py=Ay+AP*ABy
where
Ay is the y coordinate of A
AP is 2/5
ABy is the distance AB in the y coordinate
so
Py=[-5+(2/5)*(0+5)]------>Py=-3
the point P is (-2,-3)
see the attached figure