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kaheart [24]
3 years ago
10

Free Points, already got the question answered.

Mathematics
2 answers:
luda_lava [24]3 years ago
6 0

Answer:

THANKSSS

Step-by-step explanation:

SIR

serg [7]3 years ago
4 0

Answer:

Thank you!

Step-by-step explanation:

This was so generous of you fam!

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Steven, Linda, and Elliott check their lunch
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Steven, Elliot, Linda

Step-by-step explanation:

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Explain your answer !!<br><br> Have a great day <br><br> Will give brainlst
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Answer: below

Step-by-step explanation:The main environmental effects of deforestation and forest degradation include reduced biodiversity, the release of greenhouse gas emissions, forest fires, disrupted water cycles and increased soil erosion.

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3 years ago
Which expression is a factor of 10 x 2 + 11 x + 3
Eduardwww [97]
Answer: the two factors are (5x + 3) and (2x + 1)

Explanation:

I will find the two factors of 10x² + 11x + 3.

You can use either the quadratic formula of factor.

I will use the quadratic formula:

1)    

x= \frac{b^2 +/- \sqrt{b^2-4ac}  }{2a}

x=  \frac{-11+/- \sqrt{11^2-4(10)(3)} }{(2)(10)}

x = -3/5 and x = -1/2

2) the factors are: x - (-3/5) = 0 and x - (-1/2) = 0

Simplify them.

3) x - (-3/5) = 0

5x + 3 = 0

4) x - (-1/2) = 0

2x + 1 = 0

5) Then the two factors are: (5x + 3) and (2x + 1).

6) verify:

(5x + 3)(2x + 1) = 10x² + 5x + 6x + 3 = 10x² + 11x + 3 which is the original expression.
7 0
3 years ago
Work out the value of 17-5b when b=1
Artist 52 [7]

Answer:

12

Step-by-step explanation:

17 - 5b

b = 1

17 - 5(1)

17 - 5

12

3 0
3 years ago
An educational organization in California is interested in estimating the mean number of minutes per day that children between t
Hatshy [7]

Answer:

The critical value for a 98% CI is z=2.33.

The 98% confidence interval for the mean is (187.76, 194.84).

Step-by-step explanation:

We have to develop a 98% confidence interval for the mean number of minutes per day that children between the age of 6 and 18 spend watching television per day.

We know the standard deveiation of the population (σ=21.5 min.).

The sample mean is 191.3 minutes, with a sample size n=200.

The z-value for a 98% CI is z=2.33, from the table of the standard normal distribution.

The margin of error is:

E=z\cdot \sigma/\sqrt{n}=2.33*21.5/\sqrt{200}=50.095/14.142=3.54

With this margin of error, we can calculate the lower and upper bounds of the CI:

LL=\bar x-z\cdot\sigma/\sqrt{n}=191.3-3.54=187.76\\\\\\UL=\bar x+z\cdot\sigma/\sqrt{n}=191.3+3.54=194.84

The 98% confidence interval for the mean is (187.76, 194.84).

4 0
3 years ago
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