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sineoko [7]
3 years ago
5

Find the slope of the line slope=b=

Mathematics
1 answer:
Crazy boy [7]3 years ago
8 0
Slope is 100 because slope is y/x and it’s 50/0.5.
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The predecessor of 6,573,800 is
I am Lyosha [343]

The predecessor of the number 6,573,800 as given in the task content is; 6,537,799.

<h3>What is the predecessor of the number?</h3>

From the contextual meaning of the word, predecessor, it follows that it means to.find the number right before 6,573,800.

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3 0
2 years ago
What is the simplified form of the following expression? 8ab/-4b
kondaur [170]

-2a

Step-by-step explanation:

steps:1. first write the question again : 8ab/-4b

2.first 8 divide by -4=-2

3.write ' a' with -2because u don't have another 'a' down belowso that u can pair it up and cancel

so: -2a.

4. cancel 'b' on top and 'b' at the bottom.

3 0
3 years ago
I don't know how to do this or what i'm doing plz help
mote1985 [20]

recalling that d = rt, distance = rate * time.


we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

7 0
3 years ago
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