Tan(x) + tan(y)/1 - tan(x)tan(y) = sin(x)cos(y) + cos(x)sin(y)/cos(x)cos(y) - sin(x)sin(y)
tan(x + y) = sin(x + y)/cos(x + y)
tan(x + y) = tan(x + y)
Answer:
The probability of Sam is 2/5
Step-by-step explanation:
n(e)=2
n(s)=5
Pe=n(e)/n(s)
Pe=2=5
Answer:
Peanuts to Raisins!
Step-by-step explanation:
The correct answer is letter A
Answers:
1.)
C - Final exams: midterm = Q3 92 - Q1 80 = 12 and finals = Q3 85 - Q1 78 = 7, so finals exam has the smaller IQR.
2.)
B - exam median is much higher than the class median: refer to the attached image of class and exam box and whisker graph
3.)
A - <span>
IQR is a better measure of spread for movies than it is for basketball games: because the data for movies are quite wide or apart from each other than the data in the basketball games
4.)
A - </span><span>
mean for April is higher than October's mean: mean in April is 67 and mean in October is 60
5.)
A - </span><span>
Neither data set has suspected outliers: meaning there's no data that is further apart from the group or set
6.)
B - </span>
There is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical
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7.)
C - </span>
college spread is best described by the IQR. The high school spread is best described by the standard deviation: this is because of the wide range of data in the college than the data in the high school.