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3 years ago

A car travels in the direction of 135°. What is its compass heading?

Mathematics

1 answer:

viva [34]3 years ago

7 0

SE ( South East) is the answer I believe

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David wants to buy a large screen television that cost 1800$. If he buys it today ,he can save 30%.How much will the television

Irina-Kira [14]

Answer:

$1260

Step-by-step explanation:

70/100 × $1800 = $1260

3 0

3 years ago

May someone one hlrp

Marrrta [24]

52:)

explanation:

haha

5 0

3 years ago

Can someone help me find the volume please

umka2103 [35]

Answer:

See below.

Step-by-step explanation:

The figure is a cone. The formula for the volume of a cone is:

$V=\frac{1}{3}\pi r^2h$

The radius is 4.8 and the height is 2.9. Substitute:

$V=\frac{1}{3}\pi (4.8)^2(2.9)$

Use a calculator:

$V\approx69.97\text{ km}^3$

And we're done!

5 0

3 years ago

Alan spent 3 hours building a model for his science project. This was 60% of the total time he spent on the project. How many ho

Vikentia [17]

Answer:

1.8 hours i hope this helps

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates (−60,0) and (6

USPshnik [31]

LORAN follows an hyperbolic path.

The equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

The coordinates are given as:

$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

Square both sides

$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

$\mathbf{b^2 = 1100}$

The equation of an hyperbola is:

$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

So, we have:

$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

$\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$

Hence, the equation of the hyperbola is: $\mathbf{\frac{x^2}{2500} + \frac{y^2}{1100} = 1}$