The set when z = -5 is {-27, -9, -5}
<h3>How to determine the set elements?</h3>
The set is given as:
{(4z-7,z-4,z) |z is any real number}
When z=-5, we have:
4z - 7 = 4(-5) - 7 = -27
z - 4 = -5 - 4 = -9
z = -5
So, we have:
{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}
Hence, the set when z = -5 is {-27, -9, -5}
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Answer:
We want to solve the equation:
(6 - 1) + (3m)i = -12 + 27i
Where m is a complex number.
first, we can rewrite this as:
5 + 3*m*i = -12 + 27*i
3*m*i = -12 - 5 + 27*i
3*m*i = -17 + 27*i
And we can write m as:
m = a + b*i
Replacing that in the above equation we get:
3*(a + b*i)*i = -17 + 27*i
3*a*i + 3*b*i^2 = -17 + 27*i
and we know that i^2 = -1
3*a*i - 3*b = -17 + 27*i
The real part in the left (-3*b) must be equal to the real part in the right (-17)
then:
-3*b = -17
b = -17/-3 = 17/3
And the imaginary part in the left (3*a) must be equal to the imaginary part in the right (27)
then:
3*a = 27
a = 27/3.
Then the value of m is:
m = a + b*i = (27/3) + (17/3)*i
Answer:
the answer is 48
Step-by-step explanation:
