The perimeter for this case is given by:
Substituting values we have:
The area is given by:
Writing the area based on a variable we have:
We derive the area to obtain the maximum of the function:
We equal zero and clear x:
Then, the other dimension is given by:
Finally the maximum area is:
Answer:
The length and width of the plot that will maximize the area are:
The largest area that can be enclosed is:
Answer:
See answers below
Step-by-step explanation:
Given the following functions:
r(x) = x - 6
s(x) = 2x²
r(s(x)) = r(2x²)
Replacing x with 2x² in r(x) will give;
r(2x²) = 2x² - 6
r(s(x)) = 2x² - 6
(r-s)(x) = r(x) - s(x)
(r-s)(x) = x - 6 - 2x²
Rearrange
(r-s)(x) = - 2x²+x-6
(r+s)(x) = r(x) + s(x)
(r-s)(x) = x - 6 + 2x²
Rearrange
(r-s)(x) = 2x²+x-6
Answer:
48
Step-by-step explanation: