Answer:

Step-by-step explanation:
<u><em>The question is</em></u>
How do you write an equation for a circle with center (-15,11) and radius 2?
we know that
The equation of a circle in center radius form is given by

where
(h,k) is the center of the circle
r is the radius of the circle
substitute the given vales


Answer:
1.25 x 10^-8
Step-by-step explanation:
C. I and II only
The absolute value has to be greater than negative q. And p must be greater than the absolute value of q.
Answer:
see below
Step-by-step explanation:
Every vertex moves twice as far from the center of dilation as it is in the pre-image.
Perhaps the easiest image point to find is the one at lower left. In the pre-image it is 2 units left of the center of dilation, so the image point will be 2×2 = 4 units left of the center of dilation. It will be located at (-6, -2).
Other points on the image can be found either by reference to the center of dilation, or by reference to known image points. For example, the next point clockwise is 1 left and 4 up in the pre-image, so will be 2 left and 8 up from (-6, -2) in the image. That is, the pre-image point (-5, 2) becomes image point (-8, 6). You will note that (-5, 2) is 3 left and 4 up from the center of dilation, and that (-8, 6) is 6 left and 8 up from the center of dilation (twice as far away).