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Lorico [155]
3 years ago
15

The height of a hill, h(x), in a painting can be written as a

Mathematics
2 answers:
Molodets [167]3 years ago
7 0

Answer:

6in

Step-by-step explanation:

matrenka [14]3 years ago
4 0

Answer:

First option: 6\ inches

Step-by-step explanation:

<h3> The complete exercise is: "The height of a hill, h(x), in a painting can be written as a function of x, the distance from the left side of the painting. Both h(x) and x are measured in inches h(x) = -\frac{1}{5}(x)(x -13). What is the height of the hill in the painting 3 inches from the left side of the picture?</h3>

You have the following function provided in the exercise:

h(x) = -\frac{1}{5}(x)(x -13)

You know that h(x) represents the height of the hill (in inches) and "x" represents the distance from the left side of the painting (in inches)

Knowing that you can determine that, if the painting 3 inches from the left side of the picture, the value of "x" is the following:

x=3

Therefore, you need to find the value of   h(x) when  x=3 in order to solve this exercise.  

So, the next step is to substitute  x=3 into the function:

h(x) = -\frac{1}{5}(3)(3 -13)

And finally, you must evaluate in order to find h(3).

You get that this is:

h(3) = -\frac{1}{5}(3)(-10)\\\\h(3) = -\frac{1}{5}(-30)\\\\h(3)=6

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Answer:

common difference is 0.5

first term is 5

Step-by-step explanation:

<em>use </em><em>the </em><em>formula</em><em> for</em><em> </em><em>the</em><em> </em><em>nth </em><em>term </em><em>of </em><em>an </em><em>ap </em><em>Tn=</em><em>a+</em><em>(</em><em>n-1)</em><em>d</em>

<em>T12=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>T18=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em>therefore</em><em> </em><em>come </em><em>up </em><em>with </em><em>two </em><em>equations</em>

<em>T12=</em><em>a+</em><em>(</em><em>1</em><em>2</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>0</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>1</em><em>d</em><em>(</em><em>1</em><em>s</em><em>t</em><em> </em><em>equation</em><em>)</em>

<em>T18</em><em>=</em><em>a+</em><em>(</em><em>1</em><em>8</em><em>-</em><em>1</em><em>)</em><em>d</em>

<em>1</em><em>3</em><em>.</em><em>5</em><em>=</em><em>a+</em><em>1</em><em>7</em><em>d</em><em>(</em><em>2</em><em>n</em><em>d</em><em> </em><em>equation</em><em>)</em>

<em>then </em><em>solve </em><em>both </em><em>as </em><em>a </em><em>simultaneous</em><em> </em><em>equation</em>

<em>a+</em><em>1</em><em>1</em><em>d</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>1</em><em>7</em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>-6d/</em><em>-</em><em>6</em><em>=</em><em>-</em><em>3</em><em>/</em><em>-</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d=</em><em>0</em><em>.</em><em>5</em>

<em>use </em><em>one </em><em>of</em><em> the</em><em> </em><em>equations</em><em> </em><em>to </em><em>find </em><em>the </em><em>first</em><em> </em><em>term</em>

<em>a+</em><em>1</em><em>1</em><em>(</em><em>0</em><em>.</em><em>5</em><em>)</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a+</em><em>5</em><em>.</em><em>5</em><em>=</em><em>1</em><em>0</em><em>.</em><em>5</em>

<em>a=</em><em>1</em><em>0</em><em>.</em><em>5</em><em>-</em><em>5</em><em>.</em><em>5</em>

<em>a=</em><em>5</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

<em>please </em><em>mark</em><em> </em><em>as </em><em>brainliest</em>

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Stephan curry of the golden state warriors made 29 baskets some were 2 points some were 3 points. If the total points he scores
seraphim [82]
<h2>Answer: He makes 261 baskets to earn 45 points.</h2>

Step-by-step explanation:

Since we have given that

Number of points = 2 + 3 = 5

Number of baskets = 29

if he makes 45 points,

We need to find the number of baskets.

According to question, we get that

\dfrac{5}{29}=\dfrac{45}{x}\\\\5x=45\times 29\\\\x=\dfrac{45\times 29}{5}\\\\x=261

Hence, he makes 261 baskets to earn 45 points.

8 0
3 years ago
If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ?
Dominik [7]

Answer:

HJ=20\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

RT and GJ are chords that intersect at point H. If RH = 10 units, HT = 16 units, and GH = 8 units, what is the length of line segment HJ? 18 units 20 units 26 units 28 units

we know that

The <u><em>intersecting chords theorem</em></u>  is a statement that describes a relation of the four line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal

so

In this problem

(RH)(HT)=(GH)(HJ)

substitute the given values

(10)(16)=(8)(HJ)

solve for HJ

HJ=160/8\\HJ=20\ units

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