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3 years ago

11

A migrating whale is traveling at an average speed of 5.4 kilometers per hour. How far will the whale travel in 18 hours at this

rate?

1 answer:

zaharov [31]3 years ago

5 0

97.2 miles just multiply

5.4
18
_____
97.2 Remember, if there is a number behind the decimal point make sure to put a decimal point behind it in the answer

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A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

3 years ago

In a group of 1500 people, 585 have blood type A, 165 have blood type B, 690 have blood type O, and 60 have blood type AB. What

deff fn [24]

When calculating probability you need to remember that probability is:
something that you are observing divided by total number of participants.
The number you get is relative value(has value between 0 and 1) and if you want to get it in percentage (more clearly) just multiply it with 100.

In this case we are observing blood type B persons. Number of them is 165.
Total number of persons is 1500. Therefore our calculation looks like this:

165/1500 = 0.11 or the probability is 0.11*100=11%

6 0

3 years ago

Read 2 more answers

Give an example of two whole number factors with a product of 9

notsponge [240]

3 and 3 because 3x3=9

8 0

3 years ago

Draw a bar model that shows how the number of hour in March compares with the number of hours in Feburary this year.

babunello [35]

You have to actually draw one

5 0

3 years ago

Um investidor aplica R$ 1.000,00 a juros simples de 3% ao mês. Determine o valor recebido após um ano:

LenKa [72]

Responder:

$ 1360

Explicación paso a paso:

La pregunta está incompleta. Aquí está la pregunta completa.

Un inversor aplica R $ 1,000.00 a votos simples de 3% al año o más. Determinar o valor recibido después de 12 años:

Antes de determinar el valor recibido después de un año, necesitamos encontrar el interés simple sobre el dinero después de 12 años.

Interés simple = Principal * tasa * tiempo / 100

Principal dado = $ 1,000 (cantidad invertida)

Tasa = 3%

Tiempo = 1 año

SI = 1000 * 3 * 12/100

SI = 36000/100

SI = $ 360

Cantidad después de 12 años = Principal + Interés

Cantidad = $ 1000 + $ 360

Cantidad = $ 1360

7 0

2 years ago