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3 years ago

Does water have mass? How do you know?

Physics

2 answers:

Bess [88]3 years ago

8 0

every thing on this earth has it,s own mass

juin [17]3 years ago

3 0

Yes indeed. Water by golly has mass !

-- I have to do work to raise water up to a higher level from where it is.

-- When water flows over a paddle wheel, it can move a boat or do other work.

-- When I let water pour down through a turbine and turn a generator, I get electrical energy out of the generator.

-- When I put a bucket of water on one end of a see-saw, I have to put some mass on the other end to make it level.

None of these things could happen if water had no mass but energy is conserved.

And finally the kicker:

-- When I put a bucket or a water balloon on the scale, the scale says there are some pounds of weight on it.

I know that Weight=(mass)x(gravity).

So if the scale says there is weight, then there must be mass on it !

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When you shock your self because of a door knob this is an example of

Anna007 [38]

Answer:

Explanation:

Static electricity is what makes your hair stand up when you rub a balloon against it or gives you a shock from your doorknob. In static electricity, electrons are moved around mechanically (i.e. by someone rubbing two things together).

HOPE THIS HELPED AND LETTER D MADE ME LAUGH

8 0

4 years ago

Read 2 more answers

Relate the structure of water to its ability to act as a solvent

pishuonlain [190]

Explanation:

Water (H2O) as a polar covalent molecule has its arrangement of oxygen and hydrogen atoms where one end (hydrogen) has a partially positive charge while the other side (oxygen) had a partially negative charge.

It is also capable of forming hydrogen bonds with polar molecules. Each water molecule can form two hydrogen bonds involving their hydrogen atoms and two further hydrogen bonds using the hydrogen atoms attached to neighboring water molecules.

5 0

3 years ago

I need help with number 23!! Please

Juliette [100K]

Ah hah ! There's an easy way and a hard way to do this one.
If it's OK with you, I'm gonna do it the easy way, and not even
talk about the hard way !

First, let's look at a few things in this question.

-- "gravitational force between a planet and a mass"
This is just a complicated way to say "How much does the mass weigh ?"
That's what we have to find.

-- If we know the mass, how do we find the weight ?
Multiply the mass by the acceleration of gravity there.
Weight = (mass) x (gravity) .

-- Do we know the acceleration of gravity on this dark mysterious planet ?
We do if we read the second line of the question !
It's right there ... 8.8 m/s² .

-- We know the mass. We know gravity. And we know that
if you multiply them, you get the weight (forced of gravity).

I'm pretty sure that you can do the rest of the solution now.

weight = (mass) x (gravity)

Weight = (17 kg) x (8.8 m/s²)

Multiply them:

Weight = 149.6 kg-m/s²

That complicated-looking unit is the definition of a Newton !

So the weight is 149.6 Newtons. That's the answer. It's choice-A.
It's about 33.6 pounds.

When this mass is on the Earth, it weighs about 37.5 pounds.
But when it's on this planet, it only weighs about 33.6 pounds.
That's because gravity is less on this planet. (8.8 there, 9.8 on Earth)

3 0

3 years ago

The acceleration due to gravity at the surface of a planet depends on the planet's mass and size; therefore other planets will h

Ahat [919]

Answer: $1.88 m/s^2$

Explanation:

Given

initial horizontal speed of =6.55 m/s

height of rock=1.4 m

Horizontal distance=8 m

Time to travel 8 m

$8=6.55\times t$

$t=\frac{8}{6.55}=1.22 s$

Time to cover 1.4 m

$h=\frac{at^2}{2}$

$1.4=\frac{g'1.22^2}{2}$

$g'=1.88 m/s^2$

6 0

3 years ago

Two light sources can be adjusted to emit monochromatic light of any visible wavelength. The two sources are coherent, 2.04μm ap

tigry1 [53]

Answer:

Explanation:

Path difference for the observer = 2.04μm

For constructive interference

path difference = n λ

2.04μm = 5 x .408 or , 4 x .51 or 3 x .68μm

For visible wavelengths like .408 , .51 or .68 μm (400 to 700 nm) will the observer see the brightest light due to constructive interference.

B) If the two sources were not in line with the observer, but were still arranged so that one source is 2.04μm farther away from the observer than the other , in that case also , interference pattern will be visible .

c )

For destructive interference

2.04 μm = (2n+1)λ / 2

2.04μm = 3.5 x .58μm

2.04 μm = 4.5 x .45μm

So for .58μm and .45μm , destructive interference will take place

4 0

3 years ago