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steposvetlana [31]
3 years ago
5

The density of un-set concrete is 2.40 x 10 3 kg/m 3 . When a block with volume 0.0708 m 3 is

Physics
1 answer:
Dima020 [189]3 years ago
4 0

Answer:

1665 N

Explanation:

The weight of an object is the gravitational force that pulls the object towards the Earth's centre. Its magnitude is given by

W=mg

where

m is the mass of the object

g is the acceleration due to gravity

The mass of an object can be rewritten as

m=\rho V

where

\rho is the density of the material

V is the volume of the object

So the weight can be rewritten as

W=\rho V g

For the block of concrete in this problem we have:

\rho = 2.40\cdot 10^3 kg /m^3 is the density of concrete

V=0.0708 m^3 is the volume of the block

g=9.8 m/s^2is the acceleration due to gravity

So the weight of the block is:

W=(2.40\cdot 10^3)(0.0708)(9.8)=1665 N

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4. A 70.0 kg boy and a 45.0 kg girl use an elastic rope while engaged in a tug-of-war on an icy,
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Answer:

a_1 = 1.446m/s^2

Explanation:

Given

m_1 = 70.0kg -- Mass of the boy

m_2 = 45.0kg -- Mass of the girl

a_2 = 2.25m/s^2 -- Acceleration of the girl towards the boy

Required

Determine the acceleration of the boy towards the girl (a_1)

From the question, we understand that the surface is frictionless. This implies that the system is internal and the relationship between the given and required parameters is:

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Substitute values for m_1, m_2 and a_2

70.0 * a_1 = 45.0 * 2.25

Make a_1 the subject

\frac{70.0 * a_1}{70.0} = \frac{45.0 * 2.25}{70.0}

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Answer: c) Yes, since the choice of the zero of potential energy is arbitrary.

Explanation:

Potential energy depends on the frame in which you are looking at the system.

For example, the potential energy of a lifted object can be written as:

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