Question

Please solve this! I will give brainliets

Answer 1

Answer:

5 and 61

Step-by-step explanation:

Using Pythagoras' identity in the right triangles

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

(1)

c² = a² + b² = 3² + 4² = 9 + 16 = 25 ( take the square root of both sides )

c = $\sqrt{25}$ = 5

(2)

c² = a² + b² = 11² + 60² = 121 + 3600 = 3721 ( take the square root of both sides)

c = $\sqrt{3721}$ = 61