Answer:
At 90% confidence interval, the estimate of the mean breaking weight is (770.45, 778.15)
Step-by-step explanation:
Given that:
sample size n =43
sample mean x = 774.3
standard deviation = 15.4
confidence interval = 90%
At C.I of 90% , the level of significance ∝ = 1 - C.I
the level of significance ∝ = 1 - 0.90
the level of significance ∝ = 0.10
The critical value for z at this level of significance is 
= 1.64
The margin of error can be computed as follows:
Margin of error = 
Margin of error = 
Margin of error = 
Margin of error = 
Margin of error = 3.8515
The mean breaking weight for the 90% confidence interval is = 
= 
= ( 774.3 - 3.8515 < μ < 774.3 + 3.8515 )
= (770.4485, 778.1515)
(770.45, 778.15)
Answer:
x=-1
Step-by-step explanation:
Answer:
10 units
Step-by-step explanation:
7-7=0
3-(-7)=10
Answer:
0.00002 = 0.002% probability of actually having the disease
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Positive test
Event B: Having the disease
Probability of having a positive test:
0.05 of 1 - 0.000001(false positive)
0.99 of 0.000001 positive. So

Probability of a positive test and having the disease:
0.99 of 0.000001. So

What is the probability of actually having the disease

0.00002 = 0.002% probability of actually having the disease