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Gnoma [55]
3 years ago
5

Please answer this quick it is due in 20 min!

Mathematics
1 answer:
PtichkaEL [24]3 years ago
3 0

Answer:

1) 224 ounces

2) 1,820 g

3) 0.205 km

4) 5 weeks

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Simplify:$$\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}$$
bagirrra123 [75]

Answer:

5\sqrt{3}

Step-by-step explanation:

\sqrt{2\sqrt{8^2+15^2}+\sqrt{9^2+40^2}}=?\\\\1)\sqrt{8^2+15^2}=\sqrt{289}=17\\2)\sqrt{9^2+40^2}=\sqrt{1681}=41\\3)2\times17=34\\4)\sqrt{34+41}=5\sqrt{3}

All Done!

8 0
3 years ago
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BRAINIST &amp; 20 POINTS <br><br><br> *random answers will be reported*
kolezko [41]

Answer:

6-1

Step-by-step explanation:

3 0
3 years ago
Help please?? If you deposit $750 in an account that pays 8% annual interest compounded continuously, what will the balance be a
Stella [2.4K]
The formula of a continuous compound interest is
A=p e^rt
A the balance?
P present value 750
E constant
R interest rate 0.08
T time 5 years
A=750×e^(0.08×5)
A=1,118.87
7 0
4 years ago
Dan has some marbles
Andreyy89
A. Frank has 24 marbles. I found this because Dan has 15 and total is 63 so subtract 63-15= 48. 48 divided by 2 people, which are Ellie ans Dan is 24. Dan has 24 marbles.


3 0
4 years ago
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
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