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worty [1.4K]
3 years ago
11

A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the

mass of the insect to be 10 g, and assume the wings move an average downward distance of 1.0 cm during each stroke. Assuming 100 downward strokes per second, estimate the average power output of the insect.
Physics
1 answer:
Sati [7]3 years ago
4 0

Answer:

The estimated average output power of the insect is P= 0.196 Watts.

Explanation:

g= 9.8 m/s²

m= 10g = 0.01 kg

d= 1 cm = 0.01 m

sps =strokes per second= 100/s

P= ?

W= m *g = 0.098 N

F= 2 * W

F= 0.196 N

P= F * d * sps

P= 0.196 N * 0.01m * 100 s⁻¹

P= 0.196 Watts

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The positively charged atmosphere attracts negatively charged spider silk, might electrostatic force play in spider dispersal, according to a recent study.

Answer: Option C

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3 years ago
As more and more resistors are added in parallel to a circuit, the equivalent resistance of the circuit ____________ (increases,
Anestetic [448]

Answer:

Decreases, Increases

Explanation:

Resistance is parallel can be calculated using

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Then, as more resistor is added in parallel the equivalent resistance is reduced.  

Let use a simple sample

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Then, 1/Req = 1/R1 + 1/R2 + 1/R3 +....

1/Req = 1/R + 1/R + 1/R +.... 1/Rn

Req = R/n

Check attachment on how I got that.

This implies that, the equivalent resistance will always be less than the original resistance, since n>1

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B. Now, to know if the current reduces or increases

Using Ohms law

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4 years ago
PLEASE ANYONE SOLVE THIS NOW FAST PLEASE IM IN A HURRY
m_a_m_a [10]

Hello,

<u>Solution for A:</u>

Force = 3.00N

Mass = 0.50 Kgs

Time = 1.50 Seconds

According to newton's second law of motion;

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3.00 = 0.50 * a

a = 3.00/0.50 = 6.00 m/s^2

We know that acceleration = Velocity / time

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<u>Solution for B:</u>

The net force = 4.00N - 3.00N = 1.00N to the left

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Time = 3.00 Seconds

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