Answer:
the mass of the box is 51.98 kg.
Explanation:
Given;
applied horizontal force, F = 450 N
coefficient of friction, μ = 0.795
constant velocity, v = 1.2 m/s
At constant velocity, the acceleration of the object is zero and the net force will be zero.
Therefore, the mass of the box is 51.98 kg.
We can use the following equation to solve this problem:
<h3>Δp=m∣Vi−Vf∣</h3>
(Where p is the momentum change, m is mass, Vi is initial velocity, and
Vf is final velocity)
Substitute the values given to us in the question:
Δp=(0.6)∣(5.7−(−2.7)∣
Δp=4.9 kg.m/s
Final answer: 4.9kg.m/s.
The change in momentum (Δp) is defined as the change in the mass times the velocity of an object. A force is required to change the momentum of an object. This applied force can increase or decrease momentum, or even change the orientation of an object.
Learn more about momentum:
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Given :
Mass of brick, m = 2 kg.
Speed of block, v = 12 m/s .
To Find :
The momentum of the brick.
Solution :
We know, momentum of any object is given by :
Momentum = Mass × Speed
Momentum = m × v
Momentum = 2 kg × 12 m/s
Momentum = 24 kg m/s
Therefore, the momentum of the brick is 24 kg m/s .