In a cup of water it is a positive and negative charge of zero
        
             
        
        
        
 3,89,988 cm/min is the linear velocity
Given,
Diameter of CD = 12 cm
So, Radius of CD = 6 cm
CD is spinning at 10350 rev/min
Firstly , convert rev/min into rad/min
1 rev = 2π radians
10350 rev/min = 10350 × 2π
                         = 64998 rad/min
Formula used,
 where,
 where,
 is the Linear velocity
 is the Linear velocity
 is the radius
 is the radius 
 is the angular velocity
 is the angular velocity
 = 6 cm × 64998rad/min
 = 6 cm × 64998rad/min
   = 3,89,988 cm/min
Thus, linear velocity for any edge point of a 12-cm-diameter CD (compact disc) spinning at 10,350 rev/min is 389988 cm/min.
Learn more about Angular speed here brainly.com/question/540174
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Answer:
what is the passage? I don’t see it
Explanation:
 
        
             
        
        
        
<span>B. shining a bright light on the objects
and testing for decomposition </span>
<span>       
In explanation, chemical property is a
characteristic of a certain substance came from an outcome due to chemical change
or reaction. In the situation above, more specifically toxicity is involved in
the chemical property/change. Hence, when the object is tested for
decomposition. Like for an example of decomposition simply in metals, rusting. Rusting
a process of degeneration of metals. Here it works the same. Toxicity is how
much damage did a certain entity do to the object. </span>
        
                    
             
        
        
        
Answer:
Approximately  .
.
Assumption: the ball dropped with no initial velocity, and that the air resistance on this ball is negligible.
 Explanation:
Assume the air resistance on the ball is negligible. Because of gravity, the ball should accelerate downwards at a constant  near the surface of the earth.
 near the surface of the earth.
For an object that is accelerating constantly,
 ,
, 
where
 is the initial velocity of the object, is the initial velocity of the object,
 is the final velocity of the object. is the final velocity of the object.
 is its acceleration, and is its acceleration, and
 is its displacement. is its displacement.
In this case,  is the same as the change in the ball's height:
 is the same as the change in the ball's height:  . By assumption, this ball was dropped with no initial velocity. As a result,
. By assumption, this ball was dropped with no initial velocity. As a result,  . Since the ball is accelerating due to gravity,
. Since the ball is accelerating due to gravity,  .
.
 .
.
In this case,  would be the velocity of the ball just before it hits the ground. Solve for
 would be the velocity of the ball just before it hits the ground. Solve for 
 .
.
 .
.