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miv72 [106K]
3 years ago
6

Jamal walked 34 mile yesterday morning and 18 mile yesterday afternoon. What was the total distance walked by Jamal?

Mathematics
2 answers:
grin007 [14]3 years ago
8 0
The answer is 52 miles
kotykmax [81]3 years ago
8 0
It is 52 miles. 34+18= 52.
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EXPAND THE POLONOMIAL <br><br> (5a+1/2b)^2 HELPPP ASAP
stepan [7]

Answer:

25a^{2}+5ab+\frac{b^{2} }{4}

Step-by-step explanation:

(5a+\frac{1}{2} b)^{2}

1. First, write out the expression without the square

(5a+\frac{1}{2} b)(5a+\frac{1}{2} b)

2. Then use foil to multiply:

5a*5a+5a*\frac{1}{2}b+\frac{1}{2}b*5a+\frac{1}{2}b*\frac{1}{2}b

=25a^{2}+5ab+\frac{b^{2} }{4}

3. That is your answer.

8 0
3 years ago
Karen is 6 years older than her sister Michelle, and Michelle is 2 years younger than their brother David. If the sum of their a
ale4655 [162]
K\ \rightarrow\ the\ Karen's\ age\\M\ \rightarrow\ the\ Michelles\ age \\D\ \rightarrow\ the\ David's\ age\\\\K=M+6\\M=D-2\ \ \ \Rightarrow\ \ \ D=M+2\\K+M+D=62\\\\(M+6)+M+(M+2)=62\\3M+8=62\\3M=54\ /:3\\M=18\ \ \ \Rightarrow\ \ \ K=18+6=24\ \ \ and\ \ \ D=18+2=20\\\\Ans.\ Michelle\ is\ 18,\ David\ is\ 20,\ Karen\ is\ 24.
6 0
3 years ago
Solve the Equation p+5/8=15/16?
Sphinxa [80]
So the first thing you want to do when faced with two fractions with different denominators (when subtracting or adding) is to make the denominators the same. So for this equation they would turn out to be p+10/16=15/16 (because 16 is the lowest common denominator, 8 times two) so then you want to subtract 10/16 from 15/16 to isolate the variable (p) which would get: 
p=5/16
This is the final answer because it cannot be simplified.
Hope this helps!
6 0
4 years ago
How can I figure out this math problem: Stanley ran a 5 kilometer race in 30 minutes. What was his speed in kilometers per hour?
stiv31 [10]
Since the question is asking for the time units to be in hours, you want to convert 30 minutes to an hour; 0.5

We’re able to use the basic motion formula for velocity to work out this question.

Velocity = distance / time
Velocity = 5 / 0.5
Velocity = 10km/h

Therefore, Stanley’s average speed was 10 kilometres per hour. :)
3 0
3 years ago
Recently, TWA reported an on-time arrival rate of 78.4%. Assume that a later random sample of 750 flights results in 630 that ar
WINSTONCH [101]

Answer:

Step-by-step explanation:

1. Null hypothesis: u <= 0.784

Alternative hypothesis: u > 0.784

2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation

Using the formula

sd = √[{P (1-P)}/n]

Where P = 0.84 and n = 750

sd =√[{0.84( 1- 0.84)/750]}

sd=√(0.84 (0.16) /750)

SD =√(0.1344/750)

sd = √0.0001792

sd = 0.013

Then using this we can find z

z = (p - P) / sd

z = (0.84-0.784) / 0.013

z =(0.056/0.013)

z = 4.3077

3. Find the p value and use it to make conclusions...

The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.

4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.

5 0
3 years ago
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