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Maurinko [17]
3 years ago
8

A confidence interval is constructed for an unknown population proportion, p. A sample is collected, and the 95% confidence inte

rval is calculated to be 0.39 ± 0.06. Based on this information, it is most accurate to say that there is approximately 95% confidence in the assertion that:
Mathematics
1 answer:
Vikki [24]3 years ago
5 0

Answer:

There is 95% confidence that the true value of the population proportion is included in the interval (0.33, 0.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

Or, the (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the population proportion is calculated to be 0.39 ± 0.06.

The interval is:

CI = (0.33, 0.45)

This confidence interval implies that, there is 0.95  probability that the true value of the population proportion is included in the interval (0.33, 0.45).

Or, there is 95% confidence that the true value of the population proportion is included in the interval (0.33, 0.45).

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Answer:

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Step-by-step explanation:

10+11=69

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Answer:

{0, 1, 2, 3, 4} --> 96 5-digit numbers possible with this set.

Step-by-step explanation:

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link:   https://gmatclub.com/forum/how-many-five-digit-numbers-can-be-formed-using-digits-91597.html#:~:text=If%200%20is%20included%3A,numbers%20possible%20with%20this%20set.

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3 years ago
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