1. There were 11 yards mowed. Each yard is represented by an x on the line plot.
2. The most amount of gas used on any one yard was 5/8 of a gallon. The least amount of gas used was 1/8 of a gallon. The difference is (5/8)-(1/8)= (4/8)= 1/2 gallon
To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg.
<span>a) d = 1/2 (vt), = 1/2 (18 x .17), = 1.53m. </span>
<span>b) Acceleration of the ball = (v/t), = 18/.17, = 105.88m/sec^2. </span>
<span>f = (ma), = .226 x 105.88, = 23.92N. </span>
Answer:
0.4
Step-by-step explanation:
2/5 = 4/10
Answer:
The probability is 1/2
Step-by-step explanation:
The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.
When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.
As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

The values of the cummulative distribution of the Standard Normal distribution, lets denote it
, are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

Answer:
10 boys, 15 girls
Step-by-step explanation:
Original ratio: 2 boys/3 girls
let x be the scale factor of the ratio
2x plus 5 boys over 3x girls = 1 (because the # of boys/girls are the same)-------> 2x+5/3x = 1
Simplify: 2x+5=3x
Simplify: 5=x
plug x back into the original ratio: 10/15
Check: 10/15 = 2/3
10 boys + 5 boys = 15, 15/15 = 1