All categories

3 years ago

If x>2,then x2-x-6/x2-4=

1 answer:

6 0

$\frac{x^2-x-6}{x^2-4}=(*)\\------------\\x^2-x-6=0\\a=1;\ b=-1;\ c=-6\\\Delta=b^2-4ac;\ \Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\x_1=\frac{1-\sqrt{25}}{2\cdot1}=\frac{1-5}{2}=\frac{-4}{2}=-2\\\\x_2=\frac{1+\sqrt{25}}{2\cdot1}=\frac{1+5}{2}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)$
$---------------------\\x^2-4=x^2-2^2=(x-2)(x+2)\\-------------------\\\\(*)=\frac{(x+2)(x-3)}{(x-2)(x+2)}=\frac{x-3}{x-2}$

You might be interested in

One baseball team won 15 games throughout their entire season. Of all their games, this

Alex_Xolod [135]

Answer:

Step-by-step explanation:

To get the answer, you have to find what number 15 is 75 percent of.

3 0

2 years ago

The label on a package of bolts says each bolt has a diameter of 0.35 inch. To be in the package, the percent error of the diame

qaws [65]

Answer: No

Step-by-step explanation:-

Labeled diameter on the bolt = 0.35 inch

The observed diameter of the bolt= 0.33 inch

${\text {Percentage Error}}=|\frac{\text {labeled value}-{Observed value}}{\text {Observed value}}|\times 100\%$

${\text{Percentage Error}=|\frac{0.35-0.33}{0.33}|\times 100\%=6.06\%$

For the bolt to be in the package, the percent error must be less than 5%. As the percent error is 6.06% which is greater than 5%, the bolt cannot be in the package.

7 0

3 years ago

Read 2 more answers

There are 12 triangles and 3 squares. What is the simplest ratio of<br> squares to triangles?

grigory [225]

Squares : Triangles
3 : 12
Divide both sides by 3.
The simplest ratio is

1 : 4

4 0

2 years ago

Read 2 more answers

Whatis 11 -2+8 divied by 6

wel

Answer:

31 over 3

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

2 years ago

Read 2 more answers