Question

A common way to describe the bonding energy curve for secondary bonding is the '6-12' potential, which states that

Answer 1

Complete question is;

A common way to describe the bonding energy curve for secondary bonding is the "6-12" potential. which states the bonding energy, E = - A/r^(6) + B/r^(12).

Write the expression that best represents the equilibrium bond length.

Answer:

Equilibrium bond length is;

r = (2B/A)^(1/6)

Explanation:

We are given bonding energy as;

E = - A/r^(6) + B/r^(12)

Now let's find the derivative of this bonding energy with respect to r and equate to zero to find the bonding length(r).

Thus;

dE/dr = 6A/r^(7) - 12B/r^(13)

Equating to zero gives;

6A/r^(7) - 12B/r^(13) = 0

6A/r^(7) = 12B/r^(13)

Divide both sides by 6 to give;

A/r^(7) = 2B/r^(13)

2B/A = (r^(13))/(r^(7))

2B/A = r^(13 - 7)

2B/A = r^(6)

Thus, r = (2B/A)^(1/6)