The question is incomplete, the complete question is;
Calculate the volume of concentrated HCL (12 M) needed to convert 1.5 g of sodium benzoate back to benzoic acid.
Answer:
8.33 * 10^-4 L
Explanation:
Equation of the reaction;
C6H5COONa + HCl -------->>>> C6H5COOH + NaCl
Number of moles of sodium benzoate = mass/molar mass
molar mass of sodium benzoate =144.11 g/mol
mass of sodium benzoate = 1.5 g
Number of moles of sodium benzoate = 1.5g/144.11 g/mol
Number of moles of sodium benzoate = 0.01 moles
Since the reaction is 1:1, 0.01 moles of HCl reacted.
but;
n = CV
n = number of moles
C = concentration
V = volume
V = n/C
V = 0.01 moles/12 M
V = 8.33 * 10^-4 L
Answer:
Chloroplast is an organelle that is usually present in plant cells. Chloroplasts measure between 3-10 micrometers. Chloroplasts are surrounded by the envelope of two phospholipid membranes. They have pigment molecules inside them which are arranged for efficient light absorption from the Sun.
During Photosynthesis, the sunlight breaks the water molecules, and the reaction produces glucose and oxygen gas
Mass of HCl produced :15.59 g
<h3>Further explanation</h3>
Reaction
2NaCl + H₂SO₄ → 2HCl + Na₂SO₄
Excess = H₂SO₄
Limiting = NaCl
mass NaCl = 25 g
mol NaCl(MW=58.5 g/mol) :
From the equation, mol ratio NaCl : HCl = 2 : 2, so mol HCl = mol NaCl =0.427
Mass of HCl(MW=36.5 g/mol) :
As the pure element (or as an elemental mixture), or chemically bound to other elements<span> in a compound. Hope this helps!</span>
