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Mice21 [21]
2 years ago
7

Factorise fully 15 b + 20

Mathematics
2 answers:
olya-2409 [2.1K]2 years ago
6 0

Answer:

\longmapsto \: 15b + 20

\longmapsto \: 5(3b + 20)

lakkis [162]2 years ago
4 0

15b \:  + 20

  • Take 5 common from both the terms.

= 5(3b + 4)

  • 3b + 4 cannot be factorised further.

<u>Answer</u><u>:</u>

<u>5</u><u>(</u><u>3</u><u>b</u><u> </u><u>+</u><u> </u><u>4</u><u>)</u>

Hope you could understand.

If you have any query, feel free to ask.

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Complete this statement: 20 a x 2 + 25 a x + 15 a = 5 a 20 a x 2 + 25 a x + 15 a = 5 a
liubo4ka [24]

Answer:

Step-by-step explanation:

(((22•5ax2) +  25ax) +  15a) -  5  = 0  

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  20ax2 + 25ax + 15a - 5  =  

 5 • (4ax2 + 5ax + 3a - 1)  

Equation at the end of step  3  :

 5 • (4ax2 + 5ax + 3a - 1)  = 0  

Step  4  :

Equations which are never true :  

4.1      Solve :    5   =  0

4 0
3 years ago
Based on the graphs of f (x) and g(x), what must the domain of (f ⋅ g)(x) be?
bekas [8.4K]

Using the concept of domain, the domain of (f.g)(x) is given by:

{x ∈ ℝ | x ≠ 3}

---------------------

  • The domain of a function is given by all possible input values, that is, <u>on a graph, all values that the x-axis assumes.</u>
  • In the graph, <u>function f assumes all real values.</u>
  • Function g is not defined for x = 3, thus, it's domain is all real values except 3.
  • Thus, the multiplication, as fg(x) = f(x) \times g(x), will also not be defined at x = 3, and the domain of the multiplication is:

{x ∈ ℝ | x ≠ 3}

A similar problem is given at brainly.com/question/4175434

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3 years ago
Answer quickly please
Olin [163]

Answer:

Step-by-step explanation:

A. 3000/50 is 60

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The answer to this problem
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