Answer:
The level of sales in units is 7,400
Explanation:
The computation of the level of sales in units is shown below:
= (Fixed cost + target income) ÷ (Contribution margin per unit)
= ($286,200 + $106,000) ÷ ($163 per unit - $110 per unit)
= $392,200 ÷ $53 per unit
= 7,400 units
The Contribution margin per unit is
= Selling price per unit - variable cost per unit
Henec, the level of sales in units is 7,400
Answer:
correct option is c. $1,364
Explanation:
given data
purchases house = $174,000
cost of the home = $100,000
cost of the land = $74,000
solution
we know that here MACRS depreciation deduction is here on the $100000
because home only residential real property
and land is not depreciated assets
so here depreciation rate is 1.364 %
so that maximum depreciation deduction allowed is = $100,000 × 1.364
maximum depreciation deduction allowed = 1364
so correct option is c. $1,364
I think at least 3-4
Dudhdhdhdhxhxjc
Answer:
(a) 
(b) 
(c) X=4.975 percent
Explanation:
(a) Find the z-value that corresponds to 5.40 percent
.


Hence the net interest margin of 5.40 percent is 2.5 standard deviation above the mean.
The area to the left of 2.5 from the standard normal distribution table is 0.9938.The probability that a randomly selected U.S. bank will have a net interest margin that exceeds 5.40 percent is 1-0.9938=0.0062
(b) The z-value that corresponds to 4.40 percent is
The net interest margin of 4.40 percent is 0.5 standard deviation above the mean.
Using the normal distribution table, the area under the curve to the left of 0.5 is 0.6915
Therefore the probability that a randomly selected U.S. bank will have a net interest margin less than 4.40 percent is 0.6915
(c) The z-value that corresponds to 95% which is 1.65
We substitute the 1.65 into the formula and solve for X.




A bank that wants its net interest margin to be less than the net interest margins of 95 percent of all U.S. banks should set its net interest margin to 4.975 percent.
<span>Systematic indoctrination of fresh associates in the tradition's basics, regular recurrence of central costs through higher managers and team associates, and usual rituals honoring associates who show required cultural behaviors</span>