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dangina [55]
4 years ago
13

People enjoyed attending the concert in the park. Twice as many men as women attended the concert. If the total attendance was 7

14, how many women attended the concert?
Mathematics
2 answers:
d1i1m1o1n [39]4 years ago
7 0
714 divided by 3 equals 238. 238 plus 238 equals 476 (477 men-double the women). 476 plus 238 equals 714 (total).

Answer:
238 women
476 men
vazorg [7]4 years ago
5 0
Hello! A way we could solve this equation is to divide 714 by three and then multiply the quotient by 2 to get the number of men that attended. 714/3 is 238. There were 238 women that attended the concert. 238 * 2 is 476. 476 + 238 = 714. There. There were 476 men that attended the concert.
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FIND THE VALUEOF THE VARIBLE AND FILL THE BLANK.
ludmilkaskok [199]

Answer:

f = 2

g = 8

h = -9

k = 40

m = 1

Step-by-step explanation:

Equation 1:

23f - 17 = 29

Add 17 to both sides. This undoes the -17.

23f = 29 + 17

Add 17 to 29 to get 46.

23f = 46

Divide both sides by 23. This undoes the multiplication by 23.

f = 46/23

Divide 46 by 23 to get 2.

f = 2

Equation 2:

2(3g + 4) = 56

Divide both sides by 2. This undoes the multiplication by 2.

3g + 4 = 56/2

Divide 56 by 2 to get 28.

3g + 4 = 28

Subtract 4 from both sides. This undoes the +4.

3g = 28 - 4

Subtract 4 from 28 to get 24.

3g = 24

Divide both sides by 3. This undoes the multiplication by 3.

g = 24/3

Divide 24 by 3 to get 8.

g = 8

Equation 3:

h + 9 = 0

Subtract 9 from both sides. This undoes the +9.

h = 0 - 9

Any number subtracted from 0 gives its negation.

h = -9

Equation 4

3(k - 8) = 96

Divide both sides by 3. This undoes the multiplication by 3.

k - 8 = 96/3

Divide 96 by 3 to get 32.

k - 8 = 32

Add 8 to both sides. This undoes the -8.

k = 32 + 8

Add 8 to 32 to get 40.

k = 40

Equation 5:

5m - 5 = 0

Add 5 to both sides. This undoes the -5

5m = 0 + 5

Anything plus 0 gives itself.

5m = 5

Divide both sides by 5. This undoes the multiplication by 5

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3 years ago
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snow_lady [41]

Answer:

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(iii) Total SA = Area of ABCD *2 + 25*5*2 + 6*25 + 12*25

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3 years ago
Answer my question #4
Vinil7 [7]

Answer:

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Step-by-step explanation:

11.

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The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2300 employees at its Sam's Club warehouse unit
Advocard [28]

Answer:

(a) The mean is 52 and the median is 55.

(b) The first quartile is 44 and the third quartile is 60.

(c) The value of range is 33 and the inter-quartile range is 16.

(d) The variance is 100.143 and the standard deviation is 10.01.

(e) There are no outliers in the data set.

(f) Yes

Step-by-step explanation:

The data provided is:

S = {55, 56, 44, 43, 44, 56, 60, 62, 57, 45, 36, 38, 50, 69, 65}

(a)

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum x\\=\frac{1}{15}[55+ 56+ 44+ 43+ 44+ 56+ 60+ 62+ 57+ 45 +36 +38 +50 +69+ 65]\\=\frac{780}{15}\\=52

Thus, the mean is 52.

The median for odd set of values is the computed using the formula:

Median=(\frac{n+1}{2})^{th}\ obs.

Arrange the data set in ascending order as follows:

36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69

There are 15 values in the set.

Compute the median value as follows:

Median=(\frac{15+1}{2})^{th}\ obs.=(\frac{16}{2})^{th}\ obs.=8^{th}\ observation

The 8th observation is, 55.

Thus, the median is 55.

(b)

The first quartile is the middle value of the upper-half of the data set.

The upper-half of the data set is:

36, 38, 43, 44, 44, 45, 50

The middle value of the data set is 44.

Thus, the first quartile is 44.

The third quartile is the middle value of the lower-half of the data set.

The upper-half of the data set is:

56, 56, 57, 60, 62, 65, 69

The middle value of the data set is 60.

Thus, the third quartile is 60.

(c)

The range of a data set is the difference between the maximum and minimum value.

Maximum = 69

Minimum = 36

Compute the value of Range as follows:

Range =Maximum-Minimum\\=69-36\\=33

Thus, the value of range is 33.

The inter-quartile range is the difference between the first and third quartile value.

Compute the value of IQR as follows:

IQR=Q_{3}-Q_{1}\\=60-44\\=16

Thus, the inter-quartile range is 16.

(d)

Compute the variance of the data set as follows:

s^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{15-1}[(55-52)^{2}+(56-52)^{2}+...+(65-52)^{2}]\\=100.143

Thus, the variance is 100.143.

Compute the value of standard deviation as follows:

s=\sqrt{s^{2}}=\sqrt{100.143}=10.01

Thus, the standard deviation is 10.01.

(e)

An outlier is a data value that is different from the remaining values.

An outlier is a value that lies below 1.5 IQR of the first quartile or above 1.5 IQR of the third quartile.

Compute the value of Q₁ - 1.5 IQR as follows:

Q_{1}-1.5QR=44-1.5\times 16=20

Compute the value of Q₃ + 1.5 IQR as follows:

Q_{3}+1.5QR=60-1.5\times 16=80

The minimum value is 36 and the maximum is 69.

None of the values is less than 20 or more than 80.

Thus, there are no outliers in the data set.

(f)

Yes, the data provided indicates that the Walmart is meeting its goal for reducing the number of hourly employees

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