N(x)=2x+7;(x)=17, what is the value of x so that the function has a given value

Teesha is in the French club.There are 39 students in the club.The French teacher will pick 5 students at random to guide visiti

RideAnS [48]

The ratio is 5:39. We cannot simplify it, so the odds are 5:39.

6 0

3 years ago

Can anyone solve this for me????

sweet-ann [11.9K]

The old rate of pay is x and the new rate is y then we have:

y = 2x + 7

Y = 21

PART 1: 21 = 2x+7

Subtract 7 from each side:

14 = 2x

Divide both sides by 2:

X = 14 / 2

X = 7

PART 2: The internship pays $7 per hour.

7 0

3 years ago

Scrieti rezultatul sub forma de fractie ireductabila : a)1/4+5/4; b) 23/17+11/17;c) 16/93+15/93;11/14+23/14;3/16+ 15/16 ; 1 1/8+

Alborosie

Answer:

See explanations below

Step-by-step explanation:

a) 1/4+5/4

= (1+5)/4

= 6/4

= 3/2

b) 23/17+11/17

= (23+11)/17

= 34/17

= 2

c) 16/93+15/93

= (16+15)/93

= 31/93

= 1/3

d) 11/14+23/14

= (11+23)/14

= 34/14

= 17/7

e) 3/16+15/16

= (3+15)/16

= 18/16

= 9/8

f) 1 1/8 + 1 3/8

= 9/8 + 11/8

= (9+11)/8

= 20/8

= 5/2

g) 1 3/10+3 1/10;

= 13/10+31/10

= (13+31)/10

= 44/10

h) 2 3/5+3 2/5

= 13/5+17/5

= (13+17)/5

= 30/5

= 6

7 0

2 years ago

What is 20% of 30% of 40% of $50

GarryVolchara [31]

20% of $50 = $10

30% of $50 = $15

40% of $50 = $20

Multiply 20% by $50

30% by $50

40% by %50

6 0

3 years ago

(50 points and brainliest.Need help ASAP)

Aleksandr-060686 [28]

Answer: " 2x (2x - 1) (x + 1) " .

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Step-by-step explanation:

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Given:

f(x) = 9x³ + 2x² − 5x + 4 ;

g(x) = 5x³ − 7x + 4 ;

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What is: f(x) − g(x) ?

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Plug in: " 9x³ + 2x² − 5x + 4 " for: " f(x) " ;

and: " (5x³ − 7x + 4) " ; for: "g(x)" ;

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→ " f(x) − g(x) =

" 9x³ + 2x² − 5x + 4 − (5x³ − 7x + 4) " .

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Rewrite this expression as:

→ " 9x³ + 2x² − 5x + 4 − 1(5x³ − 7x + 4) " .

→ {since: " 1 " ; multiplied by "any value" ; is equal to that same value.}.

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Now, let us example the following portion of the expression:

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" − 1(5x³ − 7x + 4) "

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Note the "distributive property" of multiplication:

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→ a(b + c) = ab + ac ;

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Likewise:

→ a(b + c + d) = ab + ac + ad .

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As such:

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→ " − 1(5x³ − 7x + 4) " ;

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= (-1 * 5x³) + (-1 * 7x) + (-1 * 4) ;

= - 5x³ + (-7x) + (-4) ;

= - 5x³ − 7x − 4 ;

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Now, add the "beginning portion of the expression" ; that is:

" f(x) " ; to the expression ; which is:

→ 9x³ + 2x² − 5x + 4 ;

→ as follows:

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→ 9x³ + 2x² − 5x + 4 − 5x³ − 7x − 4 ;

→ {Note that the: " - " sign; that is;

the "negative sign", in the term: " -5x³ " ;

becomes a: " − " sign; that is; a "minus sign" .}.

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Now, combine the "like terms" of this expression; as follows:

+ 9x³ − 5x³ = + 4x³ ;

− 5x − 7x = − 2x ;

+ 4 − 4 = 0 ;

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and we have:

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→ " 4x³ + 2x² − 2x ".

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Now, to write this answer in "factored form" :

Note that among all 3 (three) terms in this expression, each term has a factor of "2" . The lowest coefficient among these 3 (three) terms is "2" ; so we can "factor out" a "2".

Also, each of the 3 (three) terms in this fraction is a coefficient to a variable. That variable takes the form of "x". The term in this expression with the variable, "x"; with the lowest degree has the variable: "x" (i.e. "x¹ = x" ) ; so we can "factor out a "2x" (rather than just the number, "2".).

So, by factoring out a "2x" ; take the first term [among the 3 (three) terms in the expression] —which is: "4x³ " .

2x * (?) = 4x³ ? ;'

↔ $\frac{4x^3}{2x} =$ ? ;

→ 4/2 = 2 ;

$\frac{x^{3}}{x} = \frac{x^3}{x^1} = x^{(3-1)} = x^{2}$ ;

As such: 2x * (2x²) = 4x³ ;

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Now, by factoring out a "2x" ; take the second term [among the 3 (three) terms in the expression] — which is: "2x² " .

2x * (?) = 2x² ? ;

↔ $\frac{2x^{2}}{2x} =$ ?

→ 2/2 = 1 ;

→ $\frac{x^{2}}{x} = \frac{x^2}{x^1}= x^{(2-1)} } = x^1 = x$ ;

As such: 2x * (x) = 2x²

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Now, by factoring out a "2x" ; take the third term [among the 3 (three) terms in the expression] — which is: " − 2x " .

2x * (?) = - 2x ;

↔ $\frac{-2x}{2x} =$ -1 ;

As such: 2x * (-1) = − 2x .

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So:

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Given the simplified expression:

→ " 4x³ + 2x² − 2x " ;

We can "factor out' a: " 2x " ; and write the this answer is: "factored form" ; as:

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"2x (2x² + x − 1 ) . "

Now, we can further factor the:

" (2x² + x − 1) " ; portion;

Note: "(2x² + x - 1)" =

2x² + 2x - 1x -1 = (2x -1) + x (2x - 1 ) =

(2x - 1) ( x + 1)

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Now, bring down the "2x" ; and write the Full "factored form" ; as follows:

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→ " 2x (2x - 1) (x + 1) " .

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Hope this helps!

Wishing you the best!

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7 0

3 years ago