Answer:
Step-by-step explanation:
- (x+y-z)²= 4xy
- (x+y-z)²- 4xy = 0
- (x+y-z)²-(2√x√y)² = 0
- (x+y-z-2√x√y)(x+y-z+2√x√y) =0
- [(√x-√y)²-z]*[(√x+√y)²-z]=0
- (√x-√y)²-z = 0 or (√x+√y)²-z = 0
We have : z^(1/2)= x^(1/2)+y^(1/2) ⇒ √z = √x + √y ⇒ z = (√x + √y)²
so (x+y-z)²= 4xy
Answer:
0.125
Step-by-step explanation:
(5 divided by 8) - ((1 divided by 4) x 2) = 0.125
73, every number is in the same range except 73
Answer: 3 < t < 4
Step-by-step explanation:
Given the following information :
Initial Velocity of projectile = 112 ft/s
Height (h) above the ground after t seconds :
h = –16t2 + 112t
To calculate the time when h exceeds 192 Feets (h >192)
That is ;
-16t^2 + 112t = > 192
-16t^2 + 112t - 192 = 0
Divide through by - 16
t^2 - 7t + 12 = 0
Factorizing
t^2 - 3t - 4t + 12 =0
t(t - 3) - 4(t - 3) = 0
(t-3) = 0 or (t-4) =0
t = 3 or t=4
Therefore, t exist between 3 and 4 for height in excess of 192ft
–16(3)^2 + 112(3) = 192 feets
–16(4)^2 + 112(4) = 192 feets
3 < t < 4