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Reil [10]
3 years ago
14

Please someone help I am so lost.

Mathematics
1 answer:
HACTEHA [7]3 years ago
7 0
You'll have to do the actual multiplication here:

  3(n+2)(4n+1)         1        4n^2 + n + 8n + 2
 -------------------- = -----  *  ---------------------------
            6                   2                    1

or (1/2) (4n^2 + 9n + 2), which, after mult., becomes

(1/2)(4n^2) + (1/2)(9n) + 1


This simplifies to 2n^2 + (9/2)n + 1

Therefore, write (1/2) in the first box and (1) in the second box.
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Every single one of those polynomials factors.  When factored, your expression looks like this: \frac{(3x-7)(x+3)}{x+3)(x-2)} * \frac{(2x+7)(x+9)}{(3x-7)(2x+7)}.  When you cancel the like factors out, what you're left with is this: \frac{1x+9}{1x-2}.  That means that b = 9, c = 1, and d = -2
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