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german
3 years ago
15

Find the lower quartile of 12, 16, 22, 34, 66, 73

Mathematics
1 answer:
Setler79 [48]3 years ago
3 0

Answer:

50 is the answer that I got.

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Two solutions of the polynomial equation are given. Use synthetic division to find any remaining solutions.
liubo4ka [24]

Answer:

The remaining solutions are -7 and 3.

Step-by-step explanation:

The synthetic division is shown in the attachment. After dividing the first two found factors from the polynomial, the remaining quadratic is ...

x^2 +4x -21 = 0

Its rational roots will be factors of -21, and the sum of their opposites will be 4. Knowing that 21 = 3·7, we can guess that the remaining roots are -7 and 3. The synthetic division confirms that. (A graph also confirms it.)

8 0
3 years ago
NEED HELP RELATIONSHIP IN TRIANGLES
GalinKa [24]

Answer:

Step-by-step explanation:

10x-13=17x-41

DO YOUR WORK

3 0
2 years ago
Read 2 more answers
Kim saved $25 in 9 weeks. At that rate, how long will it take Kim to save $175?
Simora [160]

Answer:

it would take 63 weeks to save that much money

Step-by-step explanation:

divide 25 by 9 and get 2.7 then multiply 2.7 by 63 to get 175

3 0
3 years ago
Intersection point of Y=logx and y=1/2log(x+1)
GalinKa [24]

Answer:

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

The Problem:

What is the intersection point of y=\log(x) and y=\frac{1}{2}\log(x+1)?

Step-by-step explanation:

To find the intersection of y=\log(x) and y=\frac{1}{2}\log(x+1), we will need to find when they have a common point; when their x and y are the same.

Let's start with setting the y's equal to find those x's for which the y's are the same.

\log(x)=\frac{1}{2}\log(x+1)

By power rule:

\log(x)=\log((x+1)^\frac{1}{2})

Since \log(u)=\log(v) implies u=v:

x=(x+1)^\frac{1}{2}

Squaring both sides to get rid of the fraction exponent:

x^2=x+1

This is a quadratic equation.

Subtract (x+1) on both sides:

x^2-(x+1)=0

x^2-x-1=0

Comparing this to ax^2+bx+c=0 we see the following:

a=1

b=-1

c=-1

Let's plug them into the quadratic formula:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}

x=\frac{1 \pm \sqrt{1+4}}{2}

x=\frac{1 \pm \sqrt{5}}{2}

So we have the solutions to the quadratic equation are:

x=\frac{1+\sqrt{5}}{2} or x=\frac{1-\sqrt{5}}{2}.

The second solution definitely gives at least one of the logarithm equation problems.

Example: \log(x) has problems when x \le 0 and so the second solution is a problem.

So the x where the equations intersect is at x=\frac{1+\sqrt{5}}{2}.

Let's find the y-coordinate.

You may use either equation.

I choose y=\log(x).

y=\log(\frac{1+\sqrt{5}}{2})

The intersection is (\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2}).

6 0
3 years ago
What’s is 63 fl oz;7 c; and 1.5 qt from least to greatest
Snowcat [4.5K]

Step-by-step explanation:

explain what 7 c is please and I'll write the answer in the comments:))

8 0
3 years ago
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