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Vladimir [108]
3 years ago
10

______________is the passing of a wave through an object.

Biology
2 answers:
olya-2409 [2.1K]3 years ago
6 0

Answer: Wave transmission

Explanation:

 The wave transmission is the process in which the energy are get transmitted by moving the electromagnetic waves such as radio waves and the ultraviolet rays.

The wave of the light are get absorbed by an object when the energy of an object are converted into the form of heat.

By an object the light wave can also be reflected. When the light are get reflected the transmission of wave are also get reduced  and it absorbed by the material molecules.

Airida [17]3 years ago
4 0
<h3><u>Answer;</u></h3>

Wave transmission

<u>Wave transmission</u> is the passing of a wave through an object

<h3><u>Explanation;</u></h3>
  • <em><u>Wave energy may not be reflected upon a wave hitting an object but transmitted into or through the object.</u></em>
  • During wave transmission, some energy of a wave may be absorbed within the material. Transmission of a wave through a material is due to vibration of particles in the medium and thus transfer of energy.
  • The speed at which the wave is transmitted through a material depends on the properties of the material. Waves are transmitted faster in solid materials as compared to liquid and gaseous materials.
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Answer:

Option (2).

Explanation:

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The embryonic period starts from the third week after the conception. The important organs and structure development occur during the embryonic period. The formation of three germ layers occur in this period.

Thus, the correct answer is option (2)

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What is an indicator that a chemical change has occurred?
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An owl has good night vision because its eyes can detect a light intensity as small as 5.0 × 10-13 W/m2. What is the minimum num
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Answer:

Thus, the minimum number of photons per second is 77.34

Explanation:

Light intensity, I_{min} =  5\times 10^{-13} W/m^{2}

Pupil has a diameter, d = 8.5 mm

                                      = 8.5 x 10^{-3} m

Radius of the eye, r = 4.25 x 10^{-3} m

∴ Area of the eye, A = \pi .r^{2}

                                 = 3.14\times \left ( 4.25\times 10^{-3} \right )^{2}

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Let P_{min} be the minimum number of photons.

Therefore, P_{min} = I_{min} x A

                                              = 5\times 10^{-13} x 5.6\times 10^{-5}

                                             = 2.8\times 10^{-17} W

Thus the minimum number of photons is given by

N_{min}=P_{min}/E

where E = hc/\lambda

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Therefore, N_{min} = \frac{2.8\times 10^{-17}}{3.62\times 10^{-19}}

                                              = 77.34 photons per second

Thus, the minimum number of photons per second is 77.34

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