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ohaa [14]
4 years ago
3

Suppose we are constructing a confidence interval using repeated tests of significance to develop an interval of plausible value

s. Using two-sided tests each time with the following null hypotheses, we obtain the resulting p-values.
Null p-value Null p-value
Proportion = 0.45 0.014 Proportion = 0.53 0.787
Proportion = 0.46 0.032 Proportion = 0.54 0.572
Proportion = 0.47 0.062 Proportion = 0.55 0.373
Proportion = 0.48 0.126 Proportion = 0.56 0.142
Proportion = 0.49 0.371 Proportion = 0.57 0.077
Proportion = 0.50 0.598 Proportion = 0.58 0.042
Proportion = 0.51 0.733 Proportion = 0.59 0.021
Proportion = 0.52 0.986 Proportion = 0.60 0.003


Using the results from the table, give a 90% confidence interval.

Using the results from the table, give a 95% confidence interval.

Mathematics
1 answer:
Umnica [9.8K]4 years ago
7 0

Answer:

Check the explanation

Step-by-step explanation:

90% confidence interval:

For 90% confidence level, \alpha=1-0.90=0.10.

take a look at p-values you'll notice that they are just greater than 0.10 on both upper and lower side. Those proportions would be 90% confidence interval.

Kindle check the first image for the figure table

p-value = 0.126 is just above 0.10 on lower side and p-value = 0.142 is just above 0.10 on upper side. Therefore, the 90% confidence interval is (0.48, 0.56).

--------------------------------------------------------------------------------------------------------

95% confidence interval:

For 95% confidence level, \alpha=1-0.95=0.05.

take a look at p-values you'll notice that they are just greater than 0.05 on both upper and lower side. Those proportions would be 95% confidence interval.

Kindle check the second image for the figure table

p-value = 0.062 is just above 0.05 on lower side and p-value = 0.077 is just above 0.05 on upper side. Therefore, the 95% confidence interval is (0.47, 0.57).

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Answer:

60 different ways.

Step-by-step explanation:

We have been given that you have 5 reindeer, Bloopin, Rudy, Ezekiel, Prancer, and Balthazar, and you want to have 3 fly your sleigh. You always have your reindeer fly in a single-file line. We are asked to find the number of ways in which we can arrange reindeer.

We will use permutations to solve our given problem.

The number of way to choose r objects from a set of n objects is ^nP_r=\frac{n!}{(n-r)!}.

Upon substituting our given values in permutations formula, we will get:

^5P_3=\frac{5!}{(5-3)!}

^5P_3=\frac{5!}{2!}

^5P_3=\frac{5\times 4\times 3\times 2!}{2!}

^5P_3=5\times 4\times 3

^5P_3=60

Therefore, you can arrange your reindeer in 60 different ways.

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