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lana [24]
3 years ago
6

She earns $3.10 for each hour she works and $2.30 for each bushel of apples she picks. Her goal is to earn at least $100 this we

ek.
Write an inequality that will help Tammy determine the number of hours (h) and bushels (b) she needs to reach her goal.
Mathematics
1 answer:
nika2105 [10]3 years ago
3 0

The inequality would be 3.1h + 2.3b ≥100

Step-by-step explanation:

Earning of Tammy for each hour of work= $3.1

Total hours she worked= h

Earning for picking each bushel of apple= $2.3

Total bushel she picks= b

Her goal = minimum of $100

Hence total earning from working= earning from each hour* no of hours worked

Total earning= 3.1h

Similarly, total earning from picking up apple bushels= earning from picking one bushel*no of bushels picked

Total earning= 2.3b

According to question total earning must be greater than $100

Hence, 3.1h + 2.3b ≥100

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3 years ago
How to solve <br> 12 x 3/4
tamaranim1 [39]

Answer:

9

Step-by-step explanation:

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5 0
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What is the difference between the yearly wages of the highest paying job and lowest paying job, assuming Araceli will be paid f
tigry1 [53]

-> 40 hours per week, 52 weeks a year

<u>shop and save grocers</u>

monthly wages: $3,800

hourly wages: $3800 / 160 = $23.75 per hour

yearly wages: $23.75 per hour x 40 hours per week x 52 weeks a year

= $49,400

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yearly wages: $43,000

<u>convenience store</u>

$16.50 per hour x 40 hours per week x 52 weeks a year

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4 0
3 years ago
Proportions and equations solve
kirza4 [7]
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7 0
3 years ago
URGENT HELP PLEASE!
Vaselesa [24]

Answer:

(a) x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b) x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}

Step-by-step explanation:

It is given that 0\leq x\leq 2\pi.

(a)

\sqrt{2}\sin 2x=1

\sin 2x=\dfrac{1}{\sqrt{2}}

\sin 2x=\dfrac{\pi}{4}

2x=\dfrac{\pi}{4},\dfrac{3\pi}{4},\dfrac{9\pi}{4},\dfrac{11\pi}{4}     [\because \sin x=\sin y\Rightarrow x=n\pi+(-1)^ny]

x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b)

\csc^2 x-\csc x-2=0

\csc^2 x-2\csc x+\csc x-2=0

\csc x(\csc x-2)+1(\csc x-2)=0

(\csc x+1)(\csc x-2)=0

\csc x=-1\text{ or }\csc x=2

\sin x=-1\text{ or }\sin x=\dfrac{1}{2}         [\because \sin x=\dfrac{1}{\csc x}]

x=\dfrac{3\pi}{2}\text{ or }x=\dfrac{\pi}{6},\dfrac{5\pi}{6}

Therefore, x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}.

5 0
3 years ago
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