The pythagorean theorem equation is a^2 (a squared) + b^2 (b squared) = c^2 (c squared)
so a^2+b^2=c^2
When you multiply powers, they add, and when you divide them they subtract.
So I would first add the 2^a + 2^b +2^c to get 2^(a+b+c)
Then, divide by 2^(a+b). Because when you divide powers they subtract, you will be taking away the (a+b) from the (a+b+c) and you will be left with c on its own.
The answer is 2^c
Ask: When will (4w-5)(7-w) equal zero?
When 4w-5=0 or 7-w=0
Solve each of the 2 equations above
w = 5/4 , 7
Answer:
m=-2n-13
Step-by-step explanation:
m+1=-2(n+6)
m+1=-2n-12
-1. -1
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m=-2n-13
