We assume the composite figure is a cone of radius 10 inches and slant height 15 inches set atop a hemisphere of radius 10 inches.
The formula for the volume of a cone makes use of the height of the apex above the base, so we need to use the Pythagorean theorem to find that.
h = √((15 in)² - (10 in)²) = √115 in
The volume of the conical part of the figure is then
V = (1/3)Bh = (1/3)(π×(10 in)²×(√115 in) = (100π√115)/3 in³ ≈ 1122.994 in³
The volume of the hemispherical part of the figure is given by
V = (2/3)π×r³ = (2/3)π×(10 in)³ = 2000π/3 in³ ≈ 2094.395 in³
Then the total volume of the figure is
V = (volume of conical part) + (volume of hemispherical part)
V = (100π√115)/3 in³ + 2000π/3 in³
V = (100π/3)(20 + √115) in³
V ≈ 3217.39 in³
The complete question in the attached figures N 1 and N 2
we have that
<span>the following system of inequalities:
y ≥ −3x + 1
y ≤ (1/2)x + 3
using a graph tool
see the attached figure N 3
the answer is the option
</span><span>
B)Graph of two lines that intersect at one point. Both lines are solid. One line passes through points negative 2, 2 and 0, 3 and is shaded below the line. The other line passes through points 0, 1 and 1, negative 2 and is shaded above the line.</span>
A nonlinear function that can be written on the standard form
<span><span>a<span>x2</span>+bx+c,wherea≠0</span><span>a<span>x2</span>+bx+c,wherea≠0</span></span>
is called a quadratic function.
All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is