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kherson [118]
3 years ago
6

Line segments that have the same length, or angles that have the same measure are?

Mathematics
1 answer:
almond37 [142]3 years ago
5 0

Answer:

equal or otherwise called congruent

Step-by-step explanation:

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PLZ HELP ASAP SOLVE SIMMILAR TRIANGLES
Shkiper50 [21]
For this case by similarity of triangles we can use the following relationship:
 (x) / (11) = (2) / (10)
 We clear the value of x:
 x = ((2) / (10)) * (11)
 Rewriting:
 x = ((1) / (5)) * (11)
 x = 2.2
 Equivalently:
 x = 22/10
 x = 11/5
 Answer:
 
The value of x is:
 
x = 2.2
 
Equivalently:
 
x = 11/5
6 0
4 years ago
Dani’s Neighbours paid her to take care of their bird during their vacation Danny spent four dollars of her earnings on an after
Allushta [10]

Answer:

Inequality that represents the amount paid by neighbors of Dani will be

x ≤ 8 + (4 + 16)

Step-by-step explanation:

Let the neighbors of Dani paid her to take care of their bird = $x

Danny spent on an afternoon snack = $4

She paid the amount for a new book = $16

Now the amount left with her is at least $8.

Therefore, inequality which represents the amount paid by her neighbor will be

x - 4 - 16 ≤ 8

x ≤ 8 + (4 + 16)

6 0
3 years ago
4. Which equation is true?
Pepsi [2]

Answer:

C

Step-by-step explanation:

5+3 = (-1)-(-9)

5+3 =(-1)+9

8 = 8

3 0
3 years ago
How do I solve this
anastassius [24]
\bf \cfrac{x+2}{x^2+6x-7}    so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well,  you know, if we end up with a 0 at the denominator, like   \bf \cfrac{x+2}{0}    then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.


so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=
\begin{cases}
-7\\
1
\end{cases}
\\\\\\
\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}
\\\\\\
x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
4 years ago
Number 34 please!!!!!!!!!!!!
Art [367]
The answer is D.

3x + 2 > 14, id you plug in 5 for x, it is 3 x 5 > 14 and that is true.

10 - x < 7, If you plug 5 in, it turns into 10 - 5 < 7 and that is true.
5 0
3 years ago
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