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deff fn [24]
3 years ago
10

Angelica’s bouquet of a dozen roses contains 5 white roses. The rest of the roses are pink. What fraction of the bouquet is pink

roses? There are 12 roses in a dozen.
Mathematics
2 answers:
emmasim [6.3K]3 years ago
4 0
Well, I know there are 12 roses. 
5 are white.
All you have to do is subtract 12 and 5. Once you do that you will have your answer!

Answer: 7/12 for pink roses.
Hope this helps! =) 
sesenic [268]3 years ago
4 0

Answer: (B)

Step-by-step explanation: 7/12

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What is the area of this figure (4,1)(2,2)(2,-2)(-4,-2)(-2,-5)(2,-5)
V125BC [204]

Answer:

The area of this figure is 45 square units.

8 0
2 years ago
Question 4: Diego has 25 ounces of water left from a full bottle. He
Nataliya [291]

Answer:

31.25

Step-by-step explanation:

25 is 80% of the original. Divide 25 by 8 to get 10%. This is 3.125. Multiply this by 10 to get 100%, and therefore the full amount.

6 0
3 years ago
Read 2 more answers
if you draw one card from a standard deck, what is the probability of drawing a diamond or a red card?​
Aleks [24]

Answer:

3/4 probability

probability to draw a red card = 11/26

probability to draw a diamond =1/4

probability of drawing one or other card = 35/52

# actually i am not sure

4 0
3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
Help pls due in 5 minutes
coldgirl [10]

Answer:

D

Step-by-step explanation:

2(\frac{7\times 6}{2})+3(13.1\times 7)

ANSWER IS D

4 0
2 years ago
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